20c^2=17c+63

Solution for 20c^2=17c+63 equation:

20c^2=17c+63

We move all terms to the left:

20c^2-(17c+63)=0

We get rid of parentheses

20c^2-17c-63=0

a = 20; b = -17; c = -63;
Δ = b2-4ac
Δ = -172-4·20·(-63)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-73}{2*20}=\frac{-56}{40}
=-1+2/5
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+73}{2*20}=\frac{90}{40}
=2+1/4
$